aceton

Submitted by lanas on Sun, 05/25/2014 - 19:36
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koliko grama acetona treba rastvoriti u 30g vode (p=1g/cm3) da molalnost dobijenog rastvora bude 1,25mol/kg? resenje 2,175 hvala

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milicaradenkovic - Sun, 05/25/2014 - 20:42

b=n/m(rastvaraca)

1.25=n/0.030

n=1.25*0.030=0.0375 mol

m=n*Mr=0.0375*58=2.175 g acetona