Zapremina ugljen-dioksida

Submitted by dejanbr1 on Thu, 11/14/2013 - 19:30
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Koliko se dm3 CO2 pod normalnim uslovima oslobodi dejstvom 100 cm3 36 procentne HCl gustine 1,2 g/ cm3 na karbonate?

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milicaradenkovic - Thu, 11/14/2013 - 19:45

2HCl+CO32- ----------------------->2Cl- + CO2+H2O

mr=ro*V=100*1.2=120 g

ms=w*mr=0.36*120=43.2 g

n(HCl)=ms/Mr=43.2/36.5=1.184 mol

n(CO2)=n(HCl)/2=1.184/2=0.592 mol

1 mol------------------------22.4 dm3

0.592 mol------------------x dm3

x=0.592*22.4/1=13.26 dm3 CO2