molarne velicine

Submitted by maksa244 on Tue, 01/28/2014 - 21:27
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U visku HCl rastvoreno je 6g Mg I 6,5g'Zn,kolika se zapremina vodonika oslobodila pri n.u.

 

 

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milicaradenkovic - Tue, 01/28/2014 - 22:01

1. Mg+2HCl-------------->MgCl2+H2

Zn+2HCl----------------->ZnCl2+H2

n(Mg)=m/Mr=6/24=0.25 mol

n(H2)1=n)Mg)=0.25 mol

V1(H2)=n(H2)1*Vm=0.25*22.4=5.6 l

n(Zn)=m/Mr=6.5/65=0.1 mol

n(H2)2=n(Zn)=0.1 mol

V2(H2)=n(H2)2*Vm=0.1*22.4=2.24 l

V(H20u.=V1(H2)+V2(H2)=5.6+2.24=7.84 l