VIA grupa,bakar i sumporna kiselina

Submitted by Mare97 on Wed, 02/12/2014 - 01:18
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Izracunajte koliko je kubnih cm 98% sumporne kiseline(q=1,84g/cm3) teorijski potrebno za rastvaranje 10 g Cu?

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milicaradenkovic - Wed, 02/12/2014 - 08:16

Cu+2H2SO4------------------->CuSO4+2H2O+SO2

n(Cu)=m/Mr=10/64=0.156 mol

n(kiseline)=2*n(Cu)=2*0.156=0.312 mol

ms=n(kiseline)*Mr=0.312*98=30.58 g

mr=ms/w=30.58/0.98=31.2 g

V=mr/ro=31.2/1.84=16.96 cm3 98 % H2SO4