Zapremina kiselina

Submitted by minatodorovicic on Tue, 02/18/2014 - 21:09
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Izracunajte koliko je kubnih cm 98% sumporne kiseline (gustine 1.84 g/cm3) potrebno za rastvaranje 10g bakra.

Resenje zadatka je 17,1cm3

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milicaradenkovic - Tue, 02/18/2014 - 21:14

Cu+2H2SO4---------------------->CuSO4+2H2O+SO2

Cu0(-2e-)------------------->Cu2+/1

S6+(+2e-)------------------->S4+/1

n(Cu)=m/Mr=10/64=0.156 mol

n(H2SO4)=2*n(Cu)=2*0.156=0.312 mol

ms=n(H2SO4)*Mr=0.312*98=30.576 g

mr=ms/w=30.576/0.98=31.2 g

V=mr/ro=31.2/1.84=16.96 cm3 98 % H2SO4