Napisi formulu alkena ako 0,35g ovog alkena adira 0,8 g broma
CnH2n+Br2--------------->CnH2nBr2
n(Br2)=m/Mr=0.8/160=0.005 mol
n(CnH2n)=n(Br2)=0.005 mol
Mr=m/n(CnH2n)=0.35/0.005=70 g/mol
Mr=n*Ar(C)+2*n*Ar(H)
70=12*n+2*n
70=14*n
n=70/14=5 i to je C5H10
CnH2n+Br2---------------
CnH2n+Br2--------------->CnH2nBr2
n(Br2)=m/Mr=0.8/160=0.005 mol
n(CnH2n)=n(Br2)=0.005 mol
Mr=m/n(CnH2n)=0.35/0.005=70 g/mol
Mr=n*Ar(C)+2*n*Ar(H)
70=12*n+2*n
70=14*n
n=70/14=5 i to je C5H10