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Submitted by Hemicarka5 on Mon, 12/01/2014 - 23:23
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Industrijskim postupkom iz 250m3 acetilena dobija se 160kg benzena.Izracunaj prinos benzena u procentima primjenom ovog postupka?

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milicaradenkovic - Tue, 12/02/2014 - 07:42

3C2H2----------------->C6H6

n(C6H6)=m/Mr=160*10(3)/72=2222.22 mol

n(C2H2)=V(C2H2)/Vm=250*10(3)/22.4=11160.7 mol

n1(C6H6)=n(C2H2)/3=11160.7/3=3720.23 mol

w(C6H6)=n(C6H6)/n1(C6H6)=2222.22/3720.23=0.597=59.7 %