Procentni sastav

Submitted by dejanbr1 on Tue, 09/17/2013 - 22:17
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Izracunati procentni sastav elemenata u sledecem jedinjenju:

Na2SO4 x 10H2O

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milicaradenkovic - Wed, 09/18/2013 - 09:06

w=Ar(X)/Mr(XY)

w(Na)=2*Ar((Na)/Mr(NA2SO4*10H2O)

w(Na)=2*23/322=0.143=14.3 %

w(S)=Ar(S)/Mr(Na2SO4*10H2O)

w(S)=32/322=0.0994=9.94 %

w(O)=14*Ar(O)/Mr(Na2SO4*10H2O)

w(O)=14*16/322=0.696=69.6 %

w(H)=20*Ar(H)/Mr(Na2SO4*10H2O)

w(H)=20*1/322=0.0621=6.21 %