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Submitted by Hamza on Fri, 12/18/2015 - 11:49
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Koliko je kubnih centimetara 64% azotne kiseline(gustina jr 1,394g/cm3) potrebno za pripremanje 5dm3 rastvora koncentracije 1mol/dm3?

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milicaradenkovic - Sat, 12/19/2015 - 13:00

c1*V1=c2*V2

c1=n/V=ms/Mr*V=mr*w/Mr*V=ro*w/Mr

c1=1394*0.64/63=14.16 mol/l

14.16*V1=5*1

V1=5*1/14.16

V1=0.353 l=353 ml