Azot

Submitted by Hemicarka5 on Sun, 12/15/2013 - 19:27
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Izracunajte:

a)maseni udio azota i vodonika u amonijaku

b)masu 1dm3 amonijaka.

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milicaradenkovic - Sun, 12/15/2013 - 19:48

a) maseni udeo azota u amonijaku

w(N)=Ar(N)/Mr(NH3)

w(N0=14/17=0.823=82.3 %

w(H)=100-w(N)=100-82.3=17.7 %

b) 1 mol-------------------22.4 dm3

x mol---------------------1 dm3

x=1*1/22.4=0.0446 mol NH3

m(NH3)=n(NH3)*Mr=0.0446*17=0.7582 g