Organska hemija - izomerija nezasicenih ugljovodonika

Submitted by mima316bpal on Mon, 12/16/2013 - 21:53
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Napisati moguce izomere niza CH2C(CH3)CH(CH3)CHCH2.

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milicaradenkovic - Mon, 12/16/2013 - 22:38

CH2=C(CH3)CH(CH3)CH=CH2

1. CH2=C(CH3)CH2C(CH3)=CH2

2. CH3C(CH3)=C(CH3)CH=CH2  i ukupan broj je 2